Ferrite Magnetic Design Tool. The MDT software allows application-related parameters to be calculated for all available EPCOS ferrite cores and / or materials. The Coil32 program is coil inductance calculator, that computes: one-layer and multi-layer air core inductors, coils on ferrite rings, on the pot core, flat coils on. Magnetics offers a number of inductor and transformer design tools and. Ferrite Core Documents Tape. Targeted to specific applications, each software package.

• • • Inductor Design with Magnetics Ferrite Cores The following design guide may also be. For other inquiries regarding inductor design with Magnetics ferrite cores, or submit a. Ferrite E cores and pot cores offer the advantages of decreased cost and low core losses at high frequencies.

For switching regulators, power materials are recommended because of their temperature and DC bias characteristics. By adding air gaps to these ferrite shapes, the cores can be used efficiently while avoiding saturation. These core selection procedures simplify the design of inductors for switching regulator applications. One can determine the smallest core size, assuming a winding factor of 50% and wire current carrying capacity of 500 circular mils per ampere. Only two parameters of the design applications must be known: (a) Inductance required with DC bias (b) DC current 1.

Compute the product of LI² where: L = inductance required with DC bias (millihenries) I = maximum DC output current + 1/2 AC Ripple 2. Locate the LI² value on the below. Follow this coordinate in the intersection with the first core size curve. Read the maximum nominal inductance, A L, on the Y-axis.

This represents the smallest core size and maximum A L at which saturation will be avoided. Any core size line that intersects the LI² coordinate represents a workable core for the inductor if the core’s A L value is less than the maximum value obtained on the chart. Required inductance L, core size, and core nominal inductance (A L) are known. Calculate the number of turns using where L is in millihenries. Example: If I MAX = 8 Amps; L, inductance required = 100 μHenries LI² = (0.100 mH) X (8² Amps) = 6.4 millijoules 6. Harlequin Rapidshare Downloads. There are many ferrite cores available that will support the energy required.